∫AB is the diameter,
∴∠ADB = 90°, and ∠ ABC = 90,
∴BC is o tangent,
∵DE⊙o tangent,
∴BE=DE，
∴∠EBD=∠EDB，
∫∠ADB = 90，
∴∠EBD+∠C=90，∠EDB+∠CDE=90，
∴∠C=∠EDC，
∴DE=CE，
∴be=ce；
(2)∵∠ABC=90，∠ADB=90，
∴∠C=∠ABD=∠EDC,sinC=53，
∴cosC= 1？ sin2C=23，tanC=sinCcosC=52，
In Rt△ABD, DB=ADtan∠ABD=5×25,
In Rt△BDC, BC=BDsinC=5×25×3 has praised stepping on it. What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and provide free professional consultation through Baidu Law Professional Edition. Other similar questions 2017-11-25 (2014? As shown in the figure, in △ABC, ∠ BCA = 90, ⊙O intersects AB at point P with BC as the diameter, and Q is the midpoint of AC. (1) Verify 320 18-03-02(20 12? As shown in figure 2, in Xicheng District, BC is the point with a diameter of ⊙O, A is the point above ⊙O, the intersection point C is the tangent of ⊙O, and the extension line of the intersection point BA is at point D, and the CD is taken as102017-12-/kloc-0. As shown in the figure, AB is the diameter ⊙O, point E is a point on BD, ∠ DAC = ∠ AED. (1) Verification: AC is the tangent of ⊙O; (23020 16- 12-03(20 14? The second model of Shijingshan District is shown in figure 1. In △OAB, OAB = 90°, AOB = 30 and BA = 2°. With OB as the edge, it is equilateral △OBC, D520 16-08 (2066). As shown in the figure, in Rt△ABC, point D is on the hypotenuse AB, and O with the diameter of AD is tangent to point E, connecting DE and extending 72014-1-24 (2012? As shown in the figure, AB is the diameter ⊙O, the chord CD and AB intersect at point E, and the tangent of as ⊙O passing through point A intersects with the extension line of CD at point F, such as 52016-10-27 (2013? As shown in the figure, in △ABC, AB=AC, with AC as the diameter, let ⊙O pass BC at point D, let point D pass E be FE⊥AB, and let AC 42011-05 (2065438+) As shown in the figure, in Rt△ABC, ∠ ACB = 90, ∠ CAB = 30, BC=2, and O and H are the midpoints of AB and AC sides, respectively. Will △AB8 be more similar? & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? What impact will the "network toilet" have? The price of electric cars has dropped many times. Is the quality guaranteed? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720 1532 1 1；