The reciprocal of the arithmetic square root of 7 =-√7
√7 & lt; √9=3
-√7 & gt; -3
So: the reciprocal of the arithmetic square root of 7 >; -3
How to compare the radical sign 1 1 plus 1 divided by 2 and 2: apply the idea of backward deduction;
1 1 & gt; nine
√ 1 1 & gt; √9=3
√ 1 1+ 1 & gt; 3+ 1=4
(√ 1 1+ 1)/2 & gt; 4/2=2
So: root number 1 1 plus 1 divided by 2 >; 2
I hope it helps you!