The reciprocal of the arithmetic square root of 7 =-√7

√7 & lt； √9=3

-√7 & gt； -3

So: the reciprocal of the arithmetic square root of 7 >; -3

How to compare the radical sign 1 1 plus 1 divided by 2 and 2: apply the idea of backward deduction;

1 1 & gt； nine

√ 1 1 & gt； √9=3

√ 1 1+ 1 & gt； 3+ 1=4

(√ 1 1+ 1)/2 & gt； 4/2=2

So: root number 1 1 plus 1 divided by 2 >; 2

I hope it helps you!