The atomic number of (1)Ti is 22, and the formula of its extranuclear electron arrangement is: 1s 22 p 63s 23 p 63d 44s 2, so the answer is:1S22p63s23p63d44S2;

(2) TiCl _ 4 has a low melting point, so it can be judged that its solid state is molecular crystal, so the answer is: molecule;

(3) The valence electron number of C atom in CO32-is 4+22=3, that is, three hybrid orbitals are formed, and the hybrid type is sp2；; CO32- has an atomic number of 4 and a valence electron number of 24, so NO3- and SiO 2- are isoelectrons.

So the answer is: sp2；; NO3-、SiO 32-；

(4)Ba is located in the center of the body, the number is 1, Ti is located at the vertex, the number is 8× 18= 1, O is located at the edge center, and the chemical formula is BaTiO3, so the answer is: Batio3;

(5) 1molTi, 1molCl and 5molH2O form 6molσ bond, 5molH2O contains 5x2 = 10mol σ bond, while external 1molH2O contains 2molσ bond, and * * contains 6+10+2 =.