∴ The coordinates of point A are (-1, 0), and the coordinates of point B are (0, 1).
Substitute a (- 1, 0) and b (0, 1) into y=kx+b to get k = 1b = 1.
The analytical formula of ∴ linear function is y = x+1;
∫od = 1, CD⊥x axis,
The abscissa of point ∴C is 1,
Substitute x= 1 into y=x+ 1 to get y=2.
∴C( 1,2)，
Substitute point c into y=mx to get m= 1×2=2,
The analytical formula of inverse proportional function is y = 2x.
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