(1) If the number of apples transported from orchard A to place C is x tons, the number of apples transported from orchard A to place D is (20-x) tons, and the transportation cost of apples transported from orchard A to place D is (240- 12x) yuan;

(2) The total transportation fee is expressed by a formula containing X. 。

Test center: column algebra. Topic: Chart types. Analysis:

(1) Apples transported from Orchard A to Orchard D = How many tons of apples are there in Orchard A * * The number of apples transported from Orchard A to Orchard C is X tons; The transportation cost is 12× corresponding tonnage;

(2) Total transportation cost = total transportation cost of orchards A to C+total transportation cost of orchards A to D+total transportation cost of orchards B to C+total transportation cost of orchards B to D Solution: (1)(20-x), (240-12x);

(2) 15x+ 12(20-x)+ 10( 15-x)+9[35-(20-x)]= 2x+525。

Comments: The key to solving a problem is to understand the meaning of the problem and find the equivalent relationship of the required quantity. It should be noted that according to the tonnage required by C and D, the tonnage of orchard B transported to C and D is obtained.