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Find out the answers to several math problems in grade two.
1. Solve inequality: 10-3(x+6)= 1.

-3(x+6)=-9

3(x+6)=9

(x+6)=3

x=-3

2. Decomposition factor: (3a+b) 1-a 1

=(3a+b+a)(3a+b-a)

=(4a+b)(2a+b)

3. Calculation: 2x-4x+4x-3 of 2x-6÷x-2.

=[(2x-6)/(x-2)]/[(x-3)/(x^2-4x+4)]

=[2(x-3)/(x-2)]*[(x+2)^2/(x-3)]

=2(x-2)

4. Solve the equation: 2/3 x = 3/3 x.

2/(x-3)=x-3

2=(x-3)^2

√2=x-3

X 1=-(√2)+3(√ stands for root sign)

x 1=(√2)+3

5. There is a question "Calculate: x⒉- 1 x⒉-2x+ 1 divide by x⒉+x ⒉+ 1 subtract x, where x=2007". A classmate mistakenly copied x=2007 as x=

Xχ- 1 xχ-2x+ 1 Divide by X χ+X-1Minus X.

=[(x^2-2x+ 1)/(x^2- 1)]/[(x- 1)/(x^2+x)]-x

=[(x- 1)^2/(x+ 1)(x- 1)]*[x(x+ 1)/(x- 1)]-x

=x-x

=0

6. Using the factorization factor, it is proved that 25χ-5⒓ can be divisible by 24.

Proof = 25 7-5 12

=(5^7)^2-5^ 12

=5^ 14-5^ 12

=5^ 12(5^2- 1)

=5^ 12*24

So 25χ-5⒓ can be divisible by 24.

7. Solving inequality group: 5x-6≤2(x+3) ①

4 x minus 1 < 3 x-3 ②

Simplify, acquire

x≤4

Simplify 2, get

x & gt24

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