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Answers to the exercises in the eighth grade math book of Beijing Normal University.
The fourth question on page 135 of the eighth grade mathematics book published by Beijing Normal University, 2009-04-2 1 20:46 put two identical isosceles right triangles as shown in the figure, assuming that all points and lines in the figure are in the same plane.

(1) How many triangles are there in the graph? Write them out one by one;

(2) Is there a similar triangle (excluding congruence) in the diagram? If there are, write them down one by one.

[Resolution]: (1) Look at △ABC first, * * has six triangles, plus △AFG, * * seven triangles; (2) Because ∠ DAE = ∠ B = ∠ C = 45, ∠ ADE = ∠ B+∠1= 45+∠1= ∠ BAE, the same is true.

(1) * * * There are seven triangles, which are:

△ABD△ABE△ABC△ADE△ADC△AEC△AFG .

(2) similar triangle, they are:

△ADE∽△BAE,

∠B=∠DAE, ∠ADE is a common angle, so △ADE∽△BAE.

△BAE∽△CDA,

∠DAE=∠B=∠C=45,

∠ADE =∠b+∠ 1 = 45+∠ 1 =∠BAE,

Using the same method ∠ AED = ∠ CAD, you can get △BAE∽△CDA.

△ADE∽△CDA (or △ADE∽△BAE∽△CDA)

∠C=∠ADE, ∠ADC is a common angle, so △ADE∽△CDA.

That's it.