The possible values of x are 1, 2, 3.
The distribution law of x is as follows:
P(x= 1)=C2,4/C3,5=3/5
P(x=2)=C2,3/C3,5=3/ 10
P(x=3)=C2,2/C3,5= 1/ 10
So p (x > 3) = 0, because the minimum value of the extracted number cannot be greater than 3.