The possible values of x are 1, 2, 3.

The distribution law of x is as follows:

P(x= 1)=C2，4/C3，5=3/5

P(x=2)=C2，3/C3，5=3/ 10

P(x=3)=C2，2/C3，5= 1/ 10

So p (x > 3) = 0, because the minimum value of the extracted number cannot be greater than 3.