The amount of oil obtained by each vehicle at B is 2*( 14-2x)/3.
Therefore, the total fuel consumption of each vehicle is 14+2*( 14-2x)/3.
Because the distance is round trip, they need to go to the farthest place.
[14+2 * (14-2x)/3]/2 = 7+(14-2x)/3 = 35/3-2x/3 days.
You can walk 200 meters every day, so the longest distance you can walk is 200*(35/3-2x/3).
However, since each vehicle can store 65,438+04 days of oil,
Therefore, the fuel quantity of the other three cars after refueling in area B should be satisfied.
14-x+2 *( 14-2x)/3 & lt； = 14
Get a solution, x & gt=4
So, when x=4, that is, it takes 4 days for A to B,
The other three cars can go farthest, and the farthest distance is. 200*(35/3-2*4/3)=200*9= 1800