AC=BD= 10，EG=CG，FG=GN-MN=AB-MN，

In Rt△AGE, let EG=x,

So x=( 10+x)? tan30，

X=( 10+x)×33,

Solution: x≈ 13.7,

That is EG= 13.7,

GF= 1.5-0.8=0.7，

∴EF= 13.7+0.7= 14.4.

A: The height of the flagpole EF is about14.4m..