AC=BD= 10,EG=CG,FG=GN-MN=AB-MN,
In Rt△AGE, let EG=x,
So x=( 10+x)? tan30,
X=( 10+x)×33,
Solution: x≈ 13.7,
That is EG= 13.7,
GF= 1.5-0.8=0.7,
∴EF= 13.7+0.7= 14.4.
A: The height of the flagpole EF is about14.4m..