The materials of small cartons (excluding empty covers) are:
ab*2+ac*2+bc*2=2ab+2ac+2bc(cm2)
The materials of large cartons (excluding empty covers) are:
( 1.5a * 2b)* 2+( 1.5a * 2c)* 2+(2b * 2c)* 2 = 6ab+6ac+8bc
So:
(1) The material used to make these two cartons is * * *
(2ab+2ac+2bc)+(6ab+6ac+8bc)
=8ab+8ac+ 10bc(cm2)
(2) Large cartons use more materials than small cartons.
(6ab+6ac+8bc)-(2ab+2ac+2bc)
=4ab+4ac+6bc(cm2)