Q 1: Write the number of * to make the formula hold. (4)68+34(4)+ 1(7)5=987 Q2: There are 280 balls in the lottery box, of which 82 are red, 23 are black and the rest are white. How many white balls are there than red balls? (formula calculation) < 280-82-(82+23) >-82 = < 280-82-105 >-82 = 93-82 =1(1) There are 65438 more white balls than red ones. O3: I practice swimming 550 meters in the swimming pool every day, and I swam _ _ _ _ _ meters in May. May has 365,438+0 days, so the number of days in x5 (365 365,438+0 days) is 550x365,438+0 = 65,438+07050. I practiced 550m in the swimming pool every day and swam17050m in May.

Q1:(4) 68+34 (4)+1(7) 5 = 987q2: There are more white balls than red balls: 280-(82+23+82)-82 = 280-(105. ! I hope I can help you. 2009-05-02 20:56:29 Supplement: Q3 should be: 17050m (there are 3 1 day in May! ! )

Reference: Counting machine-

oneself

Q 1: I didn't expect that.

Convert it into 957 to 4 Q2: let Bai Bo: XX = 280-82-82-23x = 280-187x = 9393-82 =11550x31=

* value will not change wo.

Reference: I

I

Q1:(4) 68+34 (4)+1(7) 5 = 987q2: There are more white balls than red ones. 280-(82+23+82)-82 = 280-( 105+82)-82 = 280- 187-82 = 93-82 = 1 1 Q3。

Q1:(4) 68+34 (4)+1(7) 5 = 987q2: There are more white balls than red balls: 280-(82+23+82)-82 = 280-(105.

Q 1。 Q2.11Q3.16500mq1Answer you 2009-05-02 17:29:55 Supplement: Q2.280-82-82.

It rang early. I thought * was the same number ... * 68+34 *+1* 5 = 987 = 468+344+175 = 987.