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On the mathematical solution of three-body (three-star operation law)?
Three-body three-star operation has several specific simple operation rules. 1.a and b are binary, and then the binary of c, a and b once again constitutes another binary of c and ab. Such a binary system includes C and AB. One year BC. B and AC. 2. That is, Samsung runs around a singularity at the same time, and abc has six combinations. bca。 Taxi and so on. 3. Even the combination of two running around one is six situations. Generally speaking, the above situation of 15 can be deduced under certain conditions, but this situation of 15 is only the operation phenomenon of 15 in Samsung. From the gravity equation, we can know the conditions that affect gravity, such as distance, mass, acceleration, speed and a constant. Mass is constant under certain conditions, but speed, acceleration, distance and so on are variables. Therefore, this 15 operation mode is unstable, and any one mode can't deduce which mode the next mode is, and when and what region (relative to the azimuth and distance of the three-body planet) are uncertain. So it is irregular, even if there is, it is very complicated, which cannot be deduced by physicists and mathematicians on earth. Think about the instability of these three stars. Can the planets here be stable? The variables are even bigger!