Bottle B contains 6-3x grams, Q 12-7x grams, (6-3X):( 12-7x)=3/7, so x= 1.
So I took a bottle of 3x = 5x = 8g.
Let one side be A, the other side be 2a, and the third side be c-3a. Because the sum of the two sides is greater than the third side, the difference between the two sides is smaller than the third side.
3a & gtc-3a,c-2a & gt; 2a,get:c/4 >; a & gtc/6
There is obviously one.
The range of a is c/6.