Let the side length of equilateral △ABC be, and the side length of equilateral △ABC be.
O is the midpoint between BC and EF,
∴AO and DO are the middle vertical lines between BC and EF.
∴∠AOC=∠DOC=900,
∴∠AOD= 1800—∠COE。
∠∠BOE = 1800—∠COE,
∴∠AOD=∠BOE。
A0 and d0 are vertical lines of BC and EF,
Get OB=a/2, OE=b/2, OA=a√3/2, OD= b√3/2.
So OA/OB=(a√3/2)/(a/2)= √3, OD/OE=( b√3/2)/(b/2)=√3.
∴△AOD∽△BOE
∴AD:BE= √3: 1
"1" Does anyone know the enrollment conditions of Rizhao Experimental Primary School? It's in the school district, but the hukou is