Solution: (1) According to the nature of translation, AB//CD and AB=CD,

Then the quadrilateral ABCD is a parallelogram,

∴AD//BC and AD = BC.

(2) Given a (-3,0) and b (-2,2), let the analytical formula of straight line AB be y=ax+b,

Then there is 0=-3a+b,

-2=-2a+b，

The solution is a=-2, b=-6,

∴ The analytical formula of straight line AB is y=-2x-6,

If CD is translated from AB, then the analytical formula of CD can be set to y=-2x+c, then C(0, c), D( 1, c-2).

Let the analytical formula of AD be y=mx+n, then there is

-3m+n=0，

m+n=c-2

The solution is m = (c-2)/4 and n = 3 (c-2)/4.

The analytical formula of ∴AD is y=(c-2)/4x+3(c-2)/4.

Then e (0 0,3 (c-2)/4), ∴ ce = c-3 (c-2)/4 = c/4+3/2.

∫S△ACD = 5，

That is, s △ ACD = s △ ace+s △ ECD =1/2× (c/4+3/2) × 3+1/2× (c/4+3/2) ×1= 5,

The solution is c=4,

∴C(0,4)？ D( 1，2)

(3) Neither will I,