Interesting math problem?

1.( 1)(294.4- 19.2×6)÷(6+8)

(2) 12.5×0.76×0.4×8×2.5

2. Multiply two numbers (1). If the multiplier is increased by 12, the multiplier remains unchanged and the product is increased by 60; If the multiplicand is constant, the multiplier increases by 12, and the product increases by 144, what is the original product?

(2) June 1990 is Friday, so what day is June 10 in 2000?

3. How many different currencies can hexagonal, dihedral and octagonal form?

4. Now put 12 pieces in the 20 squares in the figure, and put 1 piece at most in each square. It is required that the sum of the number of pieces placed in each row and column is even, and how to place them should be shown on the map.

There is a residential building, and each family subscribes to two different newspapers. Residential buildings subscribe to three newspapers, including 34 China TV newspapers, 30 Beijing Evening News and 22 reference news. So how many * * * subscribe to Beijing Evening News and reference news?

There are three playing cards on the table in a row. We already know:

(1) At least one of the two cards on the right of k is an A.

(2) One of the two cards on the left of A is also A. ..

(3) At least one of the two cards on the left side of the square is a heart.

(4) One of the two cards to the right of the heart is also a heart.

Please write these three cards in order.

7. Arrange even numbers in the table below:

four

six

eight

……

So, under which letter is the number 1998?

8. Fill in an integer in the box 14 in the figure below. If the sum of the numbers filled in any three adjacent squares is 20, we can know that the fourth square is filled with 9, and the square of 12 is filled with 7. So, what number should be filled in the eighth square?

9. Divide by natural number 1, 2,3 ...15 into two groups of numbers A and B. It is proved that the sum of two different numbers in A or B must be a complete square number.

10. Cut a piece of paper into 6 pieces, take a few pieces at will, each piece is cut into 6 pieces, then take a few pieces at will, each piece is cut into 6 pieces, and so on. Q: Can you just cut it into 1999 pieces after a limited number of times? Explain why.

Test answer 1

1.( 1)(294.4- 19.2×6)÷(6+8)

= 179.2÷ 14

= 12.8

(2) 12.5×0.76×0.4×8×2.5

=( 12.5×8)×(0.4×2.5)×0.76

= 100× 1×0.76=76

(1) Solution: When two numbers are multiplied, if the multiplicand is increased by 12, the multiplier remains unchanged and the product is increased by 60; If the multiplicand is constant, the multiplier increases by 12, and the product increases by 144, what is the original product?

Let the original title be a× b.

According to the meaning of the question: (a+ 12) × b = a× b+60.

Available: 12× b = 60

b=5

Similarly: (b+ 12) × a = a× b+ 144.

So: 12×a= 144.

a= 12

\ Original product is: 12× 5 = 60.

(2) Solution: June 1990 is Friday, so what day is June 2000 10?

There are 365 days in a year, 10 plus leap years 1992, 1996 and 2000, plus days in June, July, August and September, 10 has 10 days in October, * *.

3650+3+30+3 1+3 1+30+ 1

=3776

3776÷7=539……3

1990 June 1 Friday, so June 2000/kloc-0 June 1 is Sunday.

3. How many different currencies can hexagonal, dihedral and octagonal form?

All the money * * * has 9 yuan 60 cents.

The smallest denomination is a dime, and there are six of them. Together with the pentagon, they can form all the whole coins of a dime, a dime, a dime and a dollar coin. So you can form all the whole corners from ten cents to nine yuan and sixty cents, and ***96 different kinds of money.

Chart (○) stands for chess):

The answer is not unique.

Solution: Each family subscribes to 2 different newspapers, while * * * subscribes.

34+30+22 = 86 (copies)

So, * * * has 43.

China TV has 34 subscriptions, so this newspaper has 9 subscriptions.

Those who don't subscribe to China TV News must subscribe to Beijing Evening News and reference news.

So there are nine subscriptions to Beijing Evening News and reference news.

There are three playing cards on the table in a row. We already know:

(1) At least one of the two cards on the right of k is an A.

(2) One of the two cards on the left of A is also A. ..

(3) At least one of the two cards on the left side of the square is a heart.

(4) One of the two cards to the right of the heart is also a heart.

Please write these three cards in order.

Solution: Let the three cards on the table be A, B and C, and there are two cards on the right side of the condition (1)k, then A must be K, and at least one of B and C is A.

According to the condition (2), there is a to the left of A, so it is inevitable that both B and C are A. ..

Similarly, it can be inferred from (4) that A is the heart. From (3), C is a cube, and from (4), B is a heart.

\ The order of the three cards is: K of hearts, A of hearts and A of diamonds.

7. Arrange even numbers in the table below:

four

six

eight

……

So, under which letter is the number 1998?

Solution: As can be seen from the chart, even numbers are arranged in sequence, and every eight even numbers are arranged in the order of columns B, C, D, E, D, C, B and A. ..

Looking at column A again, the ranking order obtained by column E is cyclical with 16.

1998÷ 16= 124…… 14

Therefore, 1998 and 14 are listed in column B.

8. Fill in an integer in the box 14 in the figure below. If the sum of the numbers filled in any three adjacent squares is 20, it is known that the fourth square is filled with 9, and 12 square is filled with 7. So, what number should be filled in the eighth square?

Solution: Let A, B, C and D be numbers in any four consecutive squares.

a+b+c=20=b+c+d

\a=d

Then, the numbers in 1, 4, 7, 10, 13 are the same, and they are all 9.

Similarly, the numbers in the boxes 3, 6, 9 and 12 are all 7.

Then, the numbers in the boxes 2, 5, 8, 1 1 4 are the same, and they should all be:

20-9-7=4

9. Divide by natural number 1, 2,3 ...15 into two groups of numbers A and B. Prove that in A or B, the sum of two different numbers must be a complete square number.

Solution: Assuming that the sum of two different numbers of group A and group B is a complete square number, we can explain that this is impossible.

Let's set 1 in group A.

1+3=4= , 1+ 15= 16=

\ 3 15 are all in group B.

3+6=9=

6 must be in group a.

6+ 10= 16=

It is concluded that 10 should be in group B. At this time, the sum of two numbers in group B is a complete square number.

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