Definition Set Mz = {w | w = z (2n- 1) For any non-zero complex Z, where n belongs to N} Let A be a root of the equation x+( 1/x)=√2,

Solution: x = √ (2)/2 √ (2)/2i can be easily solved.

By z n = r n (cosnθ+isinnθ), [Demory theorem].

The combination 2n- 1 is odd, θ = 45, r= 1.

Ma={√(2)/2 √(2)/2i，-√(2)/2 √(2)/2i}

√(2)/2+√(2)/2i+[-√(2)/2-√(2)/2i]= 0

√(2)/2-√(2)/2i+[-√(2)/2+√(2)/2i]= 0

There are only two situations.

And the total ***4C2=6 methods.

P=2/6= 1/3