2.x=5a/2- 1 is derived from the original title 3x-6a+3=x-a+ 1.
Substitute x=5a/2- 1 into 4 (5a/2- 1+5) of inequality ≤120a-24 ≤16a with a≥4.
Because both A and B are less than zero, ab is greater than zero. Now compare a and ab? ,
Use a-ab? =a( 1-b？ ), because b is greater than-1, so b? Less than 1, then 1-b? Is greater than zero and a is less than zero, so a( 1-b? ) is less than zero, which means that A is less than ab? , so it is concluded that ab≥ab? ≥a
This question is a bit difficult. Are you sure the original question is an integer?
Not a non-negative integer or a positive integer? If it is a non-negative integer, otherwise:
2x-a≤0 minus 2x≤a minus x≤a/2. According to the original problem, the three non-negative integer solutions of X should be 0, 1, 2, so A can take 2*2 at the lowest, because X is not equal to 3, so A is not equal to 2*3=6, so the value range of A is [4,6], which means that this symbol is 6.
If it is a positive integer, only the values of 1, 2,3 can be taken, and the answer is [6,8].
5.get(a-3)x >； -b Because A is less than zero and a-3 is less than zero, X.
6. The solution is the same as the fourth question.
7. It took a long time to know what you wrote.
Move the inequality group into the term to get x≥2a-3b.
x≤2b-2a/3
Then 2a-3b=-5
2b-2a/3=2 Just solve the equation (don't say you can't solve the equation).
8. Is 3x/2- 1 in the middle? If so:
Multiply both sides by 2 to get -6≤3x-2≤6.
-4≤3x≤8, used for shifted items.
Divide both sides by 3 to get -4/3≤x≤8/3. Integer between-1, 0, 1 and 2.
Step 9 cut back
X & gt-b/a, so -b/a=- 1, so a = b.
10, from the original problem, it is known that 7a+2≥4a-9, and it is solved by shifting terms.
7a-4a≥- 1 1
That is, 3a≥- 1 1 gives a ≥-1/3.