(2) 1/a 1/b 5/a 5/b 1-[(5/a)+(5/b)]

(3) 1/2 1/2 x-2 =( 1/2)÷( 1/ 10)x = 7

(4)0.6

(5)x÷(8/3)-30=x÷3+30

(6) Solution: The pool will be full after X minutes. 4[( 1/ 16)+( 1/ 10)]+(x/ 10)-(x/20)= 1x = 13

(7) Deconstruction: It was originally scheduled to be completed in X days. 40x = 48 (x-16)-32x =100100 times 40 = 4,000 (pieces) A: It was originally planned to undertake 4,000 pieces. It was originally scheduled to be completed on 100.

(8) Solution: Party B and Party C need to work together for X days to complete. 1-3[( 1/9)+( 1/ 15)]= x[( 1/6)+( 1/ 15)]x = 2