Ask the sixth grade math question: As shown in the figure, the square ABCD and an isosceles right triangle EFG(EF=EG) are on the same straight line.

From the meaning of the question, the movement of 10 second is 20cm.

20- 16=4 That is to say, the overlapping distance between a square and an isosceles right triangle on the horizontal line is 4cm.

Because the angle EFG = 45° and the overlapping angle DCB = 90, the other right-angled side is equal to the right-angled side of the overlapping horizontal line, that is, 4cm. And then 4? = 16

Ok, at the first 10 second, the overlapping area is 16CM?

The rest and so on.

Hey, upstairs, I despise you. Can't the problem of grade 6 in junior high school be solved?

The Solution of Mean Value Theorem

Math teacher Miao

One-dimensional linear equation exercise.

Does the provincial award certificate of mathematical modeling have any effect on postgraduate entrance examination?

The difference between associative law and distributive law

Senior high school mathematics research topic

Math problems in the first volume of the ninth grade of junior high school (about the proportion of line segments);

20 13 Songjiang mathematics Yimo

How to find the normal vector of a plane?

Eight Mathematics Teaching Plans for Grade Six in Beijing Normal University

Mathematics teaching plan for the sixth grade of Beijing Normal University 1

Teaching objectives:

1. Explo