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- 20 13 national 2-volume mathematical answers
20 13 national 2-volume mathematical answers
The first point: when 0≤x≤ 1 and x 3 ≤ x 2, that is, x 3/2 ≤ x 2/2, so (a+2) x-x 2-x 3/2 ≥ (a+2) x-x.
Second place: Actually, we need to find an X to make -3/2x[x-2/3(a+2)] greater than 0.
Because 0
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