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How to do multiplication (-2x 2 y 3) (-3xy 2) of algebraic expressions in the first volume of the eighth grade?
Take it directly. . . . . (-2x^2 y^3)(-3xy^2)=6x^3y^5

As long as you add up the powers on x and y, the symbols in front are positive and negative.

Let me be more specific. (-2x 2y 3)(-3xy 2)=(-)*(2 * 3)* x(2+ 1)* y(3+2)= 6x 3y 5。