b/sinB=c/sinC? b/sinB=c/sin( 180 -3B)? b/sinB=c/sin3B,∴b/sinB=c/sin(2B+B)
∴b/sinb=c/(sin2bcosb+cos2bsinb)∴(2sinbcos? B+cos2BsinB)/sinB= 1/3
∴2cos? B+2cos? B- 1= 1/3? cosB=√3/3? ∴a=6cosB=2√3
This is a formula problem,
That's it. Please take it.