2. Cuboid and cone have the same volume. If the base area of a rectangle is two-fifths of the base area of a cone, then the height of the rectangle is (5/6) of the height of the cone.
3. A four-digit decimal is accurate to 5.00 after the percentile, so the maximum value of this four-digit decimal is (5.0049) and the minimum value is (4.9950).
4. The store sells shoes for a shoe factory, and both parties agree that the quantity shall not exceed 200 pairs, and the royalty shall be 8% of the total sales; If it exceeds 200 pairs, the commission will be 65,438+00% of the total sales. It is known that the commission is 9990 yuan after the first-stage entrustment. If the price of each pair is a two-digit prime number, then the price of each pair is (37 yuan).
5. Three sticks in the fifth group. (b) cannot be connected end to end to form a triangle. (Unit: cm)
A.7, 13, 19 d.25, 30, 42.
The following problem solving process
1. The original * * members of Class 3, Grade 8 were a quarter of the non-* * members, and then four people joined the league. At this time, the number of * * * members accounts for 30% of the class. How many people are there in Class Three, Grade Eight? (The question number is wrong and has been revised. )
4÷30%- 1/( 1+4)
=4÷ 10%
=40 people
2。 A project can be completed by one person in Team A 15 days, which is 5 days more than that of Team B. If two teams work together, can it be completed from July 26th to the end of July?
1÷ 1/ 15+ 1/( 15-5)
= 1÷ 1/6
=6 days
It will be finished by the end of the month.
3. At a party, 100 students won the lottery ticket with the label 1 to 100. According to the lottery ticket number, the moral principles for giving rewards are as follows:
(1) If the tag number is a multiple of 2, 2 notebooks will be awarded.
(2) The number of tags is a multiple of 3 to reward 3 notebooks.
The tag number is a multiple of 2 and a multiple of 3, and the prize can be collected repeatedly.
④ Other tag number rewards 1 notebook.
Q: How many notebooks should be prepared for this party?
100/2=50
100/3=33…… 1
100/6= 16……4
2×50+33×3+( 100-50-33+ 16)× 1
= 100+99+33
=232 copies