The first hop is left -(2n- 1), and the even hop is right +(2n- 1){ n is a number}

0- 1+3-5+7-9+……+(2×2008- 1)-(2×2009- 1)

=(0- 1+3)+(-5+7)+……+(40 15-40 13)-40 17

= 2+2+2+2 ...+2+2-40 17 {a ***(2009- 1)÷2 (+2)}

= 1004×2-40 17

=-2009

The distance between the landing point of the 2009th time and A is 2009 unit lengths.

There is another way, which may be a little coincidence, but it is also a kind of.

2: The first jump distance is point A 1 unit length.

The second jump is 2 unit lengths from point A.

The third jump is 3 unit lengths from point A.

……

And so on:

The nth hop is n unit lengths away from point a.

The distance between the landing point of the 2009th time and A is 2009 unit lengths.