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Everyone! Help me solve the three proof problems in senior two! Go, go, go. ! ! mathmatics All right, come on! ! Ok, there are extra points! !
1, because Bd is the bisector of ∠ABC.

So ∠ABD=∠CBD

Because AB=CB

∠ABD=∠CBD

BD=BD (male * * * side)

So triangle ABD and triangle CBD are congruent (angular).

So AD=CD

2、∠BHA=∠CMA

So ∠AHE=∠AMD.

Because ∠ Dam =∠EAH

AM = ah

∠CMA= ∠BHA

So the triangle AMD is equal to the triangle AHE.

3.ED is perpendicular bisector of AC.

So AE=CE

Because ED=ED

So the triangle AED is equal to the triangle CED (h 1 of the right triangle).

So ∠DAE=∠DCE=(90 degrees -∠BAE)/2=40 degrees.

So the degree of ∠C =40 degrees.