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Calculation formula of perimeter and area of mathematical body in primary school
Rectangular: S=ab{ rectangular area = length × width}

Square: s = a 2 {square area = side length × side length}

Parallelogram: S=ab{ parallelogram area = base × height}

Triangle: S=ab÷2{ triangle area = base × height ÷2}

Trapezoid: S=(a+b)×h÷2{ Trapezoid area = (upper bottom+lower bottom) × height ÷2}

Circle (perfect circle): s =πR2 {area of circle (perfect circle) = pi × radius× radius}

Ring: s =(R2-R2)×π{ area of circle (outer ring) = {pi × (outer ring radius-inner ring radius)}.

Sector: s =πr 2×n/360 {circle (sector) area = π× radius× radius× sector angle /360}

Cuboid surface area: S=2(ab+ac+bc){ cuboid surface area = (length× width+length× height+width× height )× 2}

Surface area of cube: s = 6a 2 {Surface area of cube = side length × side length× 6}

Surface area of sphere (positive sphere): s = 4πR2 {surface area of sphere (positive sphere) = pi × radius× 4}

Ellipse S=π (pi) ×a×b (where a and b are the lengths of the major axis and minor axis of the ellipse, respectively).

Cuboid: V=abc (cuboid volume = length× width× height)

Cube: v = a3;; (Cubic volume = side length × side length × side length)

Cylinder (perfect circle): v = π r 2h Volume of cylinder (perfect circle) = pi × (bottom radius× bottom radius )× height.

The volume of the above three-dimensional graphics can be summarized as: Sh (bottom area × height)

Cone (perfect circle): v = (1 /3) π r 2h Cone (perfect circle) volume = pi × bottom radius× height /3.

Pyramid: V=( 1/3)Sh Pyramid product = base area × height /3.

Column: V=Sh (column volume = bottom area × height)

Sphere: V =4/3 π r 3 Sphere volume = 4/3 (the third power of pi * radius)