(1) Because every two teams have to play a game, each team has to play a game with other 1 teams, so the number of games played by all teams is 8×7=56. Because the game is between two teams, one * * has to play 56÷2=28.

(2) In the knockout stage, 1 team will be eliminated in each game, and only 1 team will be eliminated. That is, as many teams are eliminated, just how many games have been played, and the result can be calculated according to the situation.

Solution: (1)8×(8- 1)÷2

=8×7÷2,

=56÷2,

=28 (field).

(2) Eight teams entered the competition, only 1 team won the championship, and 8- 1=7 teams were eliminated.

A: If every two teams have a game (that is, a single round robin), it will take 28 games. If the knockout stage is held and the champion is finally decided, * * * will have 7 games.

To solve this problem, it must be clear that it is a pair-by-pair elimination: 2 can only be left with1; It is concluded that the relationship between the number of participants and the number of competitions in the single round robin system is: the number of competitions = the number of participants × (the number of participants-1) ÷ 2.