Current location - Training Enrollment Network - Mathematics courses - Is it difficult to take the test in Panyu, Guangzhou? Xiaoshengchu oh
Is it difficult to take the test in Panyu, Guangzhou? Xiaoshengchu oh
It is not difficult to take the exam. There is a toilet, but there is no computer. The school spirit is not bad

Test questions love some rote questions (such as what is the equation = =).

I'll give you some formulas:

Arithmetic progression's basic formula:

The last term = the first term+(number of terms-1)× tolerance.

Number of items = (last item-first item) ÷ tolerance+1

The first item = the last item-(item number-1)× tolerance

Sum = (first item+last item) × number of items ÷2

The last item: the last digit

Item 1: the first digit

Number of items: How many digits does a * * * have?

Sum: Find the sum of a * * * number

Total number ÷ Total number of copies = average value

Formula of sum and difference problem

(sum+difference) ÷ 2 = large number

(sum and difference) ÷ 2 = decimal

And folding problems.

Sum \ (multiple-1) = decimal

Decimal × multiple = large number

(or sum-decimal = large number)

Difference problem

Difference ÷ (multiple-1) = decimal

Decimal × multiple = large number

(or decimal+difference = large number)

Tree planting problem

1 The problem of planting trees on unclosed lines can be divided into the following three situations:

(1) If trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes+1 = total length-1.

Total length = plant spacing × (number of plants-1)

Plant spacing = total length ÷ (number of plants-1)

2 If you want to plant trees at one end of the unclosed line and not at the other end, then:

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

(3) If no trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes-1 = total length-1.

Total length = plant spacing × (number of plants+1)

Plant spacing = total length ÷ (number of plants+1)

The quantitative relationship of planting trees on the closed line is as follows

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

The question of profit and loss

(Profit+Loss) ÷ Difference between two distributions = number of shares participating in distribution.

(Big profit-small profit) ÷ Difference between two distributions = number of shares participating in distribution.

(big loss-small loss) ÷ The difference between two distributions = the number of shares participating in the distribution.

encounter a problem

Meeting distance = speed × meeting time

Meeting time = meeting distance/speed and

Speed Sum = Meeting Distance/Meeting Time

Catch up with the problem

Catch-up distance = speed difference× catch-up time

Catch-up time = catch-up distance ÷ speed difference

Speed difference = catching distance ÷ catching time

Tap water problem

Downstream velocity = still water velocity+current velocity

Countercurrent velocity = still water velocity-current velocity

Still water velocity = (downstream velocity+countercurrent velocity) ÷2

Water velocity = (downstream velocity-countercurrent velocity) ÷2

Concentration problem

Solute weight+solvent weight = solution weight.

The weight of solute/solution × 100% = concentration.

Solution weight × concentration = solute weight

Solute weight-concentration = solution weight.

Profit and discount problem

Profit = selling price-cost

Profit rate = profit/cost × 100% = (selling price/cost-1) × 100%.

Up and down amount = principal × up and down percentage

Discount = actual selling price ÷ original selling price× 1 00% (discount <1)

Interest = principal × interest rate× time

After-tax interest = principal × interest rate × time × (1-20%)

1, number of copies × number of copies = total

Total copies/number of copies = number of copies

Total copies/number of copies = number of copies

2, 1 multiple× multiple = multiple

Multiply1Multiply = Multiply

Multiply/Multiply = 1 Multiply

3. Speed × time = distance

Distance/speed = time

Distance/time = speed

4. Unit price × quantity = total price

Total price/unit price = quantity

Total price ÷ quantity = unit price

5. Work efficiency × working time = total workload.

Total amount of work ÷ work efficiency = working hours

Total workload ÷ working time = working efficiency

6. Appendix+Appendix = Total

And-one addend = another addend

7. Negative-negative = difference

Negative difference = negative

Difference+Minus = Minus

8. Factor × factor = product

Product ÷ One factor = another factor

9. Dividend bonus = quotient

Dividend = divisor

Quotient × Divider = Divider

1, squared

Perimeter area side length

Perimeter = side length × 4

C=4a

Area = side length × side length

S=a×a

2. Cubic

Volume a: edge length

Surface area = side length × side length ×6

S table =a×a×6

Volume = side length × side length × side length

V=a×a×a

3. rectangular

Perimeter area side length

Circumference = (length+width) ×2

C=2(a+b)

Area = length × width

S=ab

4. Cuboid

V: volume s: area a: length b: width h: height.

(1) Surface area (L× W+L× H+W× H) ×2

S=2(ab+ah+bh)

(2) Volume = length × width × height

V=abh

5. Triangle

S area a bottom h height

Area = bottom × height ÷2

s=ah÷2

Height of triangle = area ×2÷ base.

Triangle base = area ×2÷ height

6. Parallelogram

S area a bottom h height

Area = bottom × height

S = ah

7. trapezoidal

Height of upper bottom b and lower bottom h in s area a

Area = (upper bottom+lower bottom) × height ÷2

s=(a+b)× h÷2

8, round

Area c perimeter d= diameter r= radius

(1) circumference = diameter ×∏=2×∏× radius

C=∏d=2∏r

(2) area = radius × radius×∈

9. Cylinder

V: volume h: height s; Bottom area r: bottom radius c: bottom perimeter

(1) lateral area = bottom circumference × height.

(2) Surface area = lateral area+bottom area ×2

(3) Volume = bottom area × height

(4) Volume = lateral area ÷2× radius.

10, conical

V: volume h: height s; Bottom area r: bottom radius

Volume = bottom area × height ÷3

You'd better memorize everything.

Do some questions (give me the answer on QQ, and I will give you a batch. If you can't, you can ask me, QQ: 60 1253702):

Use a stick with a length of 10 cm to cut 25 small sticks with a length of 4 cm, 3 cm and 2 cm, at least 10 cm is needed.

There is a pile of candy, which is distributed to the children in the kindergarten class. If each child is divided into 23 pieces, there will be 16 pieces left; If each person is divided into 26 capsules, and there are still 8 capsules missing, then each person is divided into () capsules, just enough to finish eating.

4.a work can be completed in 8 hours and 30 days per day, and B work can be completed in 22 days per day 10 hour. Party A takes a day off every six days and Party B takes a day off every five days. Now the two teams work together for eight hours every day. /kloc-After 0/3 days (including rest days), Party A will work alone for six hours every day, and it will take () days to complete the work.

5. given a > b > c > d > 0, then this formula is (). (Fill in "correct", "wrong" or "not necessarily correct")

6. Party A, Party B and Party C play table tennis. It is stipulated that the two of them play a game, and the loser makes way for the third person. If Party A plays 12 games, Party B plays 9 games, and Party C plays () games at most.

7. Add two cycle points to the decimal 0.6 194203875 to make it a cycle decimal. It is known that the number at100th after the decimal point is 7. This cyclic decimal is ().

8.2008 has () different divisors.

9. We agreed: =-ad-bc = ()

10. The product of an integer a and 1080 is a complete square number, so the minimum value of a is (), and this square number is ().

1 1. There are 340 grams of pure alcohol in container A and 400 grams of water in container B. Pour part of pure alcohol in container A into container B for the first time to mix alcohol with water. Pour part of the mixed liquid in container B into container A for the second time. At this time, the pure alcohol content in container A is 70%, and that in container B is 20%. Then the mixed liquid poured from container B into container A for the second time is () grams.

12. Party A, Party B and Party C are separated by 300m in turn (as shown in the figure), and Party A, Party B and Party C walk in turn every minute100m, 90m and 75m. If Party A, Party B and Party C start at the same time, the distance between Party A, Party B and Party C will be equal for the first time after () minutes.

Third, the answer (this question contains 4 small questions, each 12 points ***48 points. )

13. A school selected some students to participate in the composition competition, among which there were more boys than girls 10. As a result, 50% of the girls won the prize and 30% of the boys won the prize. The total number of winners is 27. How many students are taking part in the competition?

14. A canal with a length of170m was jointly built by two engineering teams. It is known that Team A has repaired 10 meters more than Team B. How many meters has Team B repaired less than Team A? (Mathematics Competition for Primary School Students in Huanggang City, Hubei Province)

15. There are 4 girls and 2 boys in a study group. In an exam, the number of questions they answered correctly varied, ranging from up to 65,438+00 questions to at least 4 questions. The girl who did the best job had four more questions than the boy who did the worst job, and the boy who did the best job had four more questions than the girl who did the worst job. How many questions does the boy who did the right thing have?

16.ABCD is a right-angled trapezoid as shown in the following figure, where AD= 15㎝, AB= 12㎝, BC= 18㎝, S△AED=S quadrilateral EBFD = S.

Come on! Actually, it's not difficult!