The variance is: S2 =1/n [(x1-m) 2+(x2-m) 2+...+(xn-m) 2].
Standard deviation: s = √ {1/n [(x1-m) 2+(x2-m) 2+...+(xn-m) 2]}
② If x 1, x2...xn, its variance is: s?
So the variance of kx 1, kx2...kxn is: k? s?
③ If x 1, x2...xn, its variance is: s?
Then the variance of x 1+a, x2+a, x3+a ... xn+a is: s? (No change)
(k 1, a is a non-zero constant)
④ If x 1, x2...xn, its variance is: s?
So the variance of kx 1+a, kx2+a, kx3+a ... kxn+a is: k? s?
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Speaking of young talents, there are many classes in our class! There are painting expert Han Qi, athletes'