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Solving several mathematical problems of quadratic roots
Root number 2 (root number 3+ root number 5)

Square root of = 6+radical sign 10

(Root 80+ Root 40)/ Root 5

= root number 80/ root number 5+ root number 40/ root number 5

=4+2 radical number 2

(Radical number 5+3)* (Radical number 5+2)

=5+2 radical number 5+3 radical number 5+6

= 1 1+5 radical number 5

(square root of 6+root number 2) * (square root of root number 2 of 6)

=6-2

=4

(4+ radical number 7)*(4- radical number 7)

16-7

=9

(radical a+ radical b)* (radical a- radical B)

=a-b

(radical number 3+2) 2

=3+4 radical number 3+4

=7+4 radical number 3

(2 times the root number 5- root number 2) 2

=20-4 root number 10+2

=22-4 root number 10