The following is an interesting math problem: Dragon Boat Festival is coming, and Xiaoming's father will use his life to help sell zongzi. Thirdly, he bought a gift package of 100 yuan for each customer. Xiao Ming's father said, "The price is reduced today, so you can sell 250 yuan! You return the 50 yuan to others. " Xiao Ming spent money on shopping in 20 yuan, and later everyone paid back 10 yuan. In this way, everyone handed in 90 yuan: 90*3=270 yuan, 270+20=290 (plus 20 yuan used by Xiaoming). So,1where is 0 yuan?

Solution: In fact, the money they paid should include the money used by Xiao Ming, so the algorithm of the topic is wrong. Correct solution: 270-20=250 (yuan) This 250 yuan is the amount of money that Xiaoming's father collected.

2. A shop sells zongzi. There are 1.760 zongzi stuffed with bean paste and candied dates, 60% of zongzi stuffed with bean paste and 5 1.4 zongzi stuffed with candied dates, so the number of zongzi left in the two fillings is exactly equal. If 4 yuan buys a rice dumpling stuffed with bean paste, the price is 5 yuan; A jiaozi stuffed with candied dates bought in 4.5 yuan and sold in 5 yuan. So how much profit can the merchants make after all these jiaozi are sold out?

Thinking of solving the problem: this problem is profitable, so it is the key to find out the number of all kinds of zongzi. The correct solution: suppose there are x zongzi stuffed with bean paste in the store (0.4x= 1760-x-5 14). The solution is: x=890, so there are (1760-890)780 zongzi stuffed with candied dates. Profit = (selling price-purchasing price) * Quantity of candied dates sold: (5-4.5)*780=390 (yuan) Red bean paste: (5-4)*890=890 (yuan) 390+890= 1280 (yuan) A: Both.

1. A store makes zongzi. If you make three zongzi stuffed with bean paste and four zongzi stuffed with candied dates, it will cost 37 ounces of glutinous rice. If you make two jiaozi stuffed with bean paste and five jiaozi stuffed with candied dates, you need to use 37.5 two glutinous rice. How many ounces of glutinous rice do jiaozi with bean paste and jiaozi with candied dates need?

Thinking of solving problems: list the equations correctly by using the equivalence relation given in the questions, and then get the results.

The right solution:

Jiaozi stuffed with bean paste uses glutinous rice X beam, and jiaozi stuffed with candied dates uses glutinous rice Y beam.

3x+4y=37

2x+5y=37.5

Solution: x=5, y=5.5.

Answer: The glutinous rice is used in jiaozi with bean paste and jiaozi with candied dates.

2. For a batch of zongzi, merchant A cooked it for 30 hours and merchant B cooked it for 20 hours. Now Party A has packed it for 3 hours, and then Party B has packed the rest. How many hours does Party B need to pack?

Thinking of solving the problem: treat the total amount as "unit one", and then use the equivalence relation given in the question to get the correct result.

The right solution:

B it will take x hours to pack.

1/20 * x+3 * 1/30 = 1

Solution: x= 18

A: B still needs 18.