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The function of a math problem is symmetric about the straight line Y = 1. How to find the symmetric function?
Let the symmetry function be y', then (y'+y)/2= 1, that is, y' = 2-y.

X=x' unchanged

For example, find a straight line about y=x+ 1 symmetry and let the symmetry function be y'=x'+ 1.

Then bring in y' and x' according to the above algorithm, 2-y=x+ 1, that is, y=-x+ 1.