If all ten numbers are 4 and each number is 2, then this three-digit number cannot be divisible by 8.
If divisibility is not required, then 142, 242, 342, 442, 542, 642, 742 all become feasible.
This question is meaningless.
The following analysis and calculation are based on the fact that ten digits are 2 and one digit is 4:
This number can be expressed in the form of a24.
Because 24 is an integer multiple of 8, a00 after removing 24 is also an integer multiple of 8.
In this way, a may be 4 or 8, but it can only be 424, because 824 is divided by 8 to get 3 digits.
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