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How to do the problem on page 64 of Math Exercise II of Beijing Normal University Edition in Grade Six of Primary School?
12345 * * 5 * 4 = 20.

The possibility of composition 12 is 1|20.

Because 12 is fixed, the probability of winning the first prize is 1|5, and the probability of winning the second prize is 1|4, so1| 5 *1| 4 =1| 20.

The following answer is

The possibility of the tenth digit 2 is 1|5* 1= 1|5.

What is the probability that the composition number is not 43? 1- 1|20= 19|20.

What is the probability that the number of components is greater than 3 1? 3 * 1 | 5- 1 | 20 = 1 1 | 20.

What is the probability that the number is even? 2* 1|5=2|5.

What is the possibility that the number of components can be divisible by 5 4|5* 1|4=4|20?

Take out five cards to form five digits, * * with 5*4*3*2* 1= 120.

The possibility of greater than 30000 is that 3|5 starts with 3, 4, 5, which is greater than 30000. * * There are 4 * 3 * 2 *1* 3 = 7272 |120 = 3 | 5.

The probability of less than 50000 is 4|5.

The possibility of being divisible by 3 is 1, because as long as it is divisible by 3, the possibility is 1.

Possibility of not being divisible by 2 3 | 5

Divisible by 2 and 3 at the same time is 1-9| 15=2|5.

The possibility of being divisible by both 3 and 5 is 1|5.

The possibility of being divisible by 2, 3 and 5 at the same time is zero.