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Junior high school entrance examination math problem! ! ! Somebody please.
Suppose there is XYZ of a, b and c, then ① {15x+10y+10z = 2900} ② {24x+12y+18z = m} ③ {25x}

50z = 7000④ ④-③: 25z = 3250z =130z for ③: 25x = 500x = 20 for ①:10y =1300y =130.

Substitute into ②: m = 24× 20+12×130+18×130m = 4380.

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