Current location - Training Enrollment Network - Mathematics courses - What are the math problems in the second issue of Running Man in the second season?
What are the math problems in the second issue of Running Man in the second season?
***5 questions, as follows:

1. Chickens and rabbits live in the same cage. Chickens and rabbits have 35 heads and 94 feet. How many chickens and rabbits are there?

Solution: Set X chicken and Y rabbit.

2x+4y=94 (feet)

X+y=35 (head)

X=23? y= 12

Foreign businessmen want 62 ribbons in red, yellow and blue, of which 3/5 are yellow ribbons and 3/4 are blue ribbons. How many ribbons can they buy?

Solution: Foreign businessmen can buy X red ribbon, Y yellow ribbon and Z blue ribbon;

According to the meaning of the question, there are:

x+y+z=62

3/5 times = 2/3 years

y=3/4z

X=20 y= 18 z=24。

Foreign businessmen starting from 3,500 yuan want to buy toilet plungers and washboards, and the number of toilet plungers is 3/5 of that of washboards, while the toilet plungers in 20 yuan and 8 yuan just cost 500 yuan. How many toilet plungers and washboards can foreign businessmen buy?

Solution: Suppose foreign businessmen can buy X toilet plunger and Y washboard;

According to the meaning of the question, there are:

20x+8y=500

x=3/5y

X= 15 y=25。

4. Foreign investors should buy 48 necklaces and hair bands * * *, each necklace 10 yuan and each hair band 13 yuan, but not more than 580 yuan and hair bands, which are easy to sell. Foreign businessmen should buy as many hair bands as possible. How many hair bands can they buy at most?

Solution: foreign businessmen can buy up to x hair bands, so they buy 48-x necklaces;

According to the meaning of the question, there are:

10(48-x)+ 13x & lt; =580

X should be an integer.

Let x (maximum) =33.

Foreign businessmen from 5.500 yuan want to buy 100 plush toys. 100 There should be a lion and a chicken in the plush toy, 6 yuan for each lion and 2 yuan for each chicken. How many lions and chickens can foreign businessmen buy with this 500 yuan?

Solution: Suppose foreign businessmen can buy X lions and Y chickens;

According to the meaning of the question, there are:

x+y= 100

6x+2y=500

The solution is x=75 y=25.