∴⊿CMP∽⊿APN, cm//A.
Let M(x, 6)
The parabolic equation is: y=-2(x+3)(x- 1).
Its symmetry axis is x=( 1-3)/2=- 1.
∴M(0,6)
The equation of straight line AC is: y=-2x+2.
If c is CM⊥AC, then it is ⊿MCP∽⊿ANP.
The CM equation is: y-6 =1/2 (x+2) = = > x-2y+ 14=0
4x 2+9x+2 = 0 = = > x 1=-2,x2=- 1/4
Substituting parabola results in y2=55/8.
∴M2(- 1/4,55/8)