∴⊿CMP∽⊿APN, cm//A.

Let M(x, 6)

The parabolic equation is: y=-2(x+3)(x- 1).

Its symmetry axis is x=( 1-3)/2=- 1.

∴M(0,6)

The equation of straight line AC is: y=-2x+2.

If c is CM⊥AC, then it is ⊿MCP∽⊿ANP.

The CM equation is: y-6 =1/2 (x+2) = = > x-2y+ 14=0

4x 2+9x+2 = 0 = = > x 1=-2，x2=- 1/4

Substituting parabola results in y2=55/8.

∴M2(- 1/4,55/8)