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- Mathematical answers of Zhanjiang Ermo 20 17
Mathematical answers of Zhanjiang Ermo 20 17
Solution: (1) As shown in the figure, in the isosceles trapezoid CDEF, if DH is high, then EH=AB=x and DH=EH? tan∠FED=34x
∴s=xy+ 12(x+3x)×34x=xy+32x2=6，
∴y=6x？ 32x
∫x > 0，y>0
∴6x？ 32x>0,∴0
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