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Summary of a compulsory knowledge point in mathematics
First, the understanding of numbers

(1) Integer and Decimal

(2) the divisibility of numbers

(3) Fractions and decimals

Second, the operation of numbers

(A) the significance and law of the four operations

(2) Elementary arithmetic

(3) Operating rules and characteristics

(4) Written test questions

(5) Simple equation

Third, the application problem.

(A) simple application questions

(2) Compound application questions

(3) the application of scores and percentages

(4) Using equations to solve application problems.

Fourth, the elementary knowledge of geometry.

(1) lines and angles

(2) Plane graphics

(3) Three-dimensional graphics

Verb (abbreviation for verb) ratio and proportion

(A) than the understanding

(B) the understanding of proportion

(3) Application problems

Size of intransitive verbs

Seven. statistical chart

I believe my information is helpful to you. I wish you study hard and make progress every day.

References:

General review of mathematics in primary school graduating class

Formula set

General operating rules

65438+ 0× number of shares per share = total number of shares = total number of shares = number of shares = number of shares.

2 1 multiple× multiple = multiple1multiple = multiple/multiple = 1 multiple

3 speed × time = distance distance ÷ speed = time distance ÷ time = speed

4 unit price × quantity = total price/total price = total quantity/quantity = unit price

5 working efficiency × working time = total work amount ÷ working efficiency = working time ÷ total work amount ÷ working time = working efficiency

6 addend+addend = and-one addend = another addend.

7 minuend-minuend = difference minuend-difference = minuend difference+minuend = minuend

8 factor × factor = product product ÷ one factor = another factor

9 Dividend Divider = quotient divisor = divisor quotient × divisor = dividend

Calculation formula of mathematical graphics in primary schools

1 square c perimeter s area a side length

Perimeter = side length ×4 C=4a

Area = side length × side length S=a×a

2 cubic v: volume a: side length

Surface area = side length × side length× ×6 S Table =a×a×6

Volume = side length × side length × side length v = a× a× a.

3 rectangle c perimeter s area a side length

Circumference = (length+width) ×2 C=2(a+b)

Area = length × width S=ab

4 cuboid v: volume s: area a: length b: width h: height

Surface area (length× width+length× height+width× height )× 2s = 2 (AB+AH+BH)

Volume = length× width× height V=abh

5 triangle s area a base h height

Area = bottom × height ÷2 s=ah÷2

Height of triangle = area ×2÷ base of triangle = area ×2÷ height

6 parallelogram s area a bottom h height

Area = bottom × height s=ah

7 trapezoid s area a upper bottom b lower bottom h height

Area = (upper bottom+lower bottom) × height ÷2 s=(a+b)× h÷2.

8 circle s area c perimeter ∏ d= diameter r= radius

Circumference = diameter x ∏ = 2 x ∏× radius C=∏d=2∏r

Area = radius × radius ×∈

9 cylinder v: volume h: height s; Bottom area r: bottom radius c: bottom perimeter

Lateral area = perimeter of bottom× high surface area = lateral area+area of bottom× 2.

Volume = bottom area × high volume = lateral area ÷2× radius.

10 cone v: volume h: height s; Bottom area r: bottom radius

Volume = bottom area × height ÷3

Primary school olympiad formula

Formula of sum and difference problem

(sum+difference) ÷ 2 = large number (sum-difference) ÷ 2 = decimal.

Summation formula and multiple problems

Sum ÷ (multiple-1) = decimal × multiple = large number (or sum-decimal = large number)

Formula of differential multiple problems

Difference ÷ (multiple-1) = decimal × multiple = large number (or decimal+difference = large number)

Tree planting formula

1 The problem of planting trees on unclosed lines can be divided into the following three situations:

(1) If trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes+1 = total length-1.

Total length = plant spacing × (number of plants-1)

Plant spacing = total length ÷ (number of plants-1)

2 If you want to plant trees at one end of the unclosed line and not at the other end, then:

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

(3) If no trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes-1 = total length-1.

Total length = plant spacing × (number of plants+1)

Plant spacing = total length ÷ (number of plants+1)

The quantitative relationship of planting trees on the closed line is as follows

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

Formula of profit and loss problem

(Profit+Loss) ÷ Difference between two distributions = number of shares participating in distribution.

(Big profit-small profit) ÷ Difference between two distributions = number of shares participating in distribution.

(big loss-small loss) ÷ The difference between two distributions = the number of shares participating in the distribution.

The formula of encounter problem

Meeting distance = speed × meeting time

Meeting time = meeting distance/speed and

Speed Sum = Meeting Distance/Meeting Time

The formula for tracing the problem

Catch-up distance = speed difference× catch-up time

Catch-up time = catch-up distance ÷ speed difference

Speed difference = catching distance ÷ catching time

Tap water problem

Downstream velocity = still water velocity+current velocity

Countercurrent velocity = still water velocity-current velocity

Still water velocity = (downstream velocity+countercurrent velocity) ÷2

Water velocity = (downstream velocity-countercurrent velocity) ÷2

Formula of concentration problem

Solute weight+solvent weight = solution weight.

The weight of solute/solution × 100% = concentration.

Solution weight × concentration = solute weight

Solute weight-concentration = solution weight.

Profit formula and discount problem

Profit = selling price-cost

Profit rate = profit/cost × 100% = (selling price/cost-1) × 100%.

Up and down amount = principal × up and down percentage

Discount = actual selling price ÷ original selling price× 1 00% (discount <1)

Interest = principal × interest rate× time

After-tax interest = principal × interest rate × time × (1-20%)

Number of copies × number of copies = total number of copies

Total copies/number of copies = number of copies

Total copies/number of copies = number of copies

2 1 multiple × multiple = multiple

Multiply1Multiply = Multiply

Multiply/Multiply = 1 Multiply

3 Speed × Time = Distance

Distance/speed = time

Distance/time = speed

4 unit price × quantity = total price

Total price/unit price = quantity

Total price ÷ quantity = unit price

5 Work efficiency × working hours = total workload.

Total amount of work ÷ work efficiency = working hours

Total workload ÷ working time = working efficiency

6 addend+addend = sum

And-one addend = another addend

7 minuend-minuend = difference

Negative difference = negative

Difference+Minus = Minus

8 factor × factor = product

Product ÷ One factor = another factor

Dividend = quotient

Dividend = divisor

Quotient × Divider = Divider

Calculation formula of mathematical graphics in primary schools

1 square

Perimeter area side length

Perimeter = side length ×4

C=4a

Area = side length × side length

S=a×a

2 cubic meters

Volume a: edge length

Surface area = side length × side length ×6

S table =a×a×6

Volume = side length × side length × side length

V=a×a×a

3 rectangle

Perimeter area side length

Circumference = (length+width) ×2

C=2(a+b)

Area = length × width

S=ab

4 cuboid

V: volume s: area a: length b: width h: height.

(1) Surface area (L× W+L× H+W× H) ×2

S=2(ab+ah+bh)

(2) Volume = length × width × height

V=abh

5 triangle

S area a bottom h height

Area = bottom × height ÷2

s=ah÷2

Height of triangle = area ×2÷ base.

Triangle base = area ×2÷ height

6 parallelogram

S area a bottom h height

Area = bottom × height

S = ah

7 trapezoid

Height of upper bottom b and lower bottom h in s area a

Area = (upper bottom+lower bottom) × height ÷2

s=(a+b)× h÷2

8 laps

Area c perimeter d= diameter r= radius

(1) circumference = diameter ×∏=2×∏× radius

C=∏d=2∏r

(2) area = radius × radius×∈

Cylinder 9

V: volume h: height s; Bottom area r: bottom radius c: bottom perimeter

(1) lateral area = bottom circumference × height.

(2) Surface area = lateral area+bottom area ×2

(3) Volume = bottom area × height

(4) Volume = lateral area ÷2× radius.

10 cone

V: volume h: height s; Bottom area r: bottom radius

Volume = bottom area × height ÷3

Total number ÷ Total number of copies = average value

Formula of sum and difference problem

(sum+difference) ÷ 2 = large number

(sum and difference) ÷ 2 = decimal

And folding problems.

Sum \ (multiple-1) = decimal

Decimal × multiple = large number

(or sum-decimal = large number)

Difference problem

Difference ÷ (multiple-1) = decimal

Decimal × multiple = large number

(or decimal+difference = large number)

Respondent: Zheng Yifan 94- probationary period 6-25 15:28.

Primary school mathematics formula:

1, the perimeter of the rectangle = (length+width) ×2 C=(a+b)×2.

2. The circumference of a square = side length ×4 C=4a.

3. Area of rectangle = length× width S=ab

4. Square area = side length x side length s = a.a = a.

5. Area of triangle = base × height ÷2 S=ah÷2.

6. parallelogram area = bottom x height S=ah

7. trapezoidal area = (upper bottom+lower bottom) × height ÷ 2s = (a+b) h ÷ 2.

8. Diameter = Radius× 2D = 2r Radius = Diameter ÷2 r= d÷2

9. The circumference of a circle = π× diameter = π× radius× 2c = π d = 2π r.

10, circular area = pi × radius× radius? =πr

1 1, the surface area of a cuboid = (length× width+length× height+width× height) × 2.

12, cuboid volume = length× width× height V =abh.

13, the surface area of the cube = side length × side length× ×6 S =6a.

14, volume of cube = side length x side length x side length v = a.a.a = a.

15, lateral area of cylinder = circumference of bottom circle × height S=ch.

16, surface area of cylinder = upper and lower bottom area+side area.

s = 2πr+2πRH = 2π(d÷2)+2π(d÷2)h = 2π(c÷2÷π)+Ch

17, cylinder volume = bottom area × height V=Sh

V=πr h=π(d÷2) h=π(C÷2÷π) h

18, volume of cone = bottom area × height ÷3.

v = sh÷3 =πr h÷3 =π(d÷2)h÷3 =π(c÷2÷π)h÷3

19, cuboid (cube, cylinder)

1, number of copies × number of copies = total number of copies/number of copies = total number of copies/number of copies = number of copies.

2. 1 multiple× multiple = multiple1multiple = multiple/multiple = 1 multiple

3. Speed × time = distance/speed = time/distance/time = speed.

4. Unit price × quantity = total price ÷ unit price = total quantity ÷ quantity = unit price

5. Work efficiency × working hours = total workload ÷ work efficiency = working hours ÷ total workload ÷ working hours = work efficiency.

6. Appendix+Appendix = sum, and-one addend = another addend.

7. Minus-Minus = Minus-Minus = Minus+Minus = Minus

8. Factor × factor = product ÷ one factor = another factor.

9. Dividend = quotient dividend = divisor quotient × divisor = dividend

Calculation formula of mathematical graphics in primary schools

1, square c perimeter s area a side length perimeter = side length× 4c = 4a area = side length× side length s = a× a.

2. Cube V: volume A: side surface area = side length × side length× 6s table =a×a×6 volume = side length× side length× side length V = a× a× a.

3. rectangular

Perimeter area side length

Circumference = (length+width) ×2

C=2(a+b)

Area = length × width

S=ab

4. Cuboid

V: volume s: area a: length b: width h: height.

(1) Surface area (L× W+L× H+W× H) ×2

S=2(ab+ah+bh)

(2) Volume = length × width × height

V=abh

5 triangle

S area a bottom h height

Area = bottom × height ÷2

s=ah÷2

Height of triangle = area ×2÷ base.

Triangle base = area ×2÷ height

6 parallelogram

S area a bottom h height

Area = bottom × height

S = ah

7 trapezoid

Height of upper bottom b and lower bottom h in s area a

Area = (upper bottom+lower bottom) × height ÷2

s=(a+b)× h÷2

8 laps

Area c perimeter d= diameter r= radius

(1) circumference = diameter ×∏=2×∏× radius

C=∏d=2∏r

(2) area = radius × radius×∈

Cylinder 9

V: volume h: height s; Bottom area r: bottom radius c: bottom perimeter

(1) lateral area = bottom circumference × height.

(2) Surface area = lateral area+bottom area ×2

(3) Volume = bottom area × height

(4) Volume = lateral area ÷2× radius.

10 cone

V: volume h: height s; Bottom area r: bottom radius

Volume = bottom area × height ÷3

Total number ÷ Total number of copies = average value

Sum-difference problem

(sum+difference) ÷ 2 = large number

(sum and difference) ÷ 2 = decimal

And folding problems.

Sum \ (multiple-1) = decimal

Decimal × multiple = large number

(or sum-decimal = large number)

Difference problem

Difference ÷ (multiple-1) = decimal

Decimal × multiple = large number

(or decimal+difference = large number)

Tree planting problem

1 The problem of planting trees on unclosed lines can be divided into the following three situations:

(1) If trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes+1 = total length-1.

Total length = plant spacing × (number of plants-1)

Plant spacing = total length ÷ (number of plants-1)

2 If you want to plant trees at one end of the unclosed line and not at the other end, then:

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

(3) If no trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes-1 = total length-1.

Total length = plant spacing × (number of plants+1)

Plant spacing = total length ÷ (number of plants+1)

The quantitative relationship of planting trees on the closed line is as follows

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

The question of profit and loss

(Profit+Loss) ÷ Difference between two distributions = number of shares participating in distribution.

(Big profit-small profit) ÷ Difference between two distributions = number of shares participating in distribution.

(big loss-small loss) ÷ The difference between two distributions = the number of shares participating in the distribution.

encounter a problem

Meeting distance = speed × meeting time

Meeting time = meeting distance/speed and

Speed Sum = Meeting Distance/Meeting Time

Catch up with the problem

Catch-up distance = speed difference× catch-up time

Catch-up time = catch-up distance ÷ speed difference

Speed difference = catching distance ÷ catching time

Tap water problem

Downstream velocity = still water velocity+current velocity

Countercurrent velocity = still water velocity-current velocity

Still water velocity = (downstream velocity+countercurrent velocity) ÷2

Water velocity = (downstream velocity-countercurrent velocity) ÷2

Concentration problem

Solute weight+solvent weight = solution weight.

The weight of solute/solution × 100% = concentration.

Solution weight × concentration = solute weight

Solute weight-concentration = solution weight.

Profit and discount problem

Profit = selling price-cost

Profit rate = profit/cost × 100% = (selling price/cost-1) × 100%.

Up and down amount = principal × up and down percentage

Discount = actual selling price ÷ original selling price× 1 00% (discount <1)

Interest = principal × interest rate× time

After-tax interest = principal × interest rate × time × (1-20%)

Time unit conversion

1 century = 100 1 year =65438+ February.

The big month (3 1 day) includes:1\ 3 \ 5 \ 7 \ 8 \10 \ 65438+February.

Abortion (30 days) includes: April \ June \ September \165438+1October.

February 28th in a normal year and February 29th in a leap year.

There are 365 days in a normal year and 366 days in a leap year.

1 day =24 hours 1 hour =60 minutes.

1 point = 60s 1 hour = 3600s product = bottom area × height V=Sh.