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When an object is weighed by a spring scale described by Xiaodong, the relationship between the extension length of the spring and the suspension quality is as follows (straight line).
Elongated length of spring scale = measured length-original length

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Quality? Quantity (grams)? 200? 400? 600? 800? 1000? 1200

Spring elongation (cm)? 2 4 ? 6 ? 8 10 ? 12

When not weighing, the spring is fixed at 8 cm.

Spring extension? /? Mass = 2/200 = 1/200 = 0.005.

The elongation of the spring is proportional to the mass of the object. For every 65,438+0g object added, the spring will be extended by 0.005cm (for every 65,438+00g object weighed, the spring will be extended by 0.5cm).

With the increase of the mass of the object, the connecting line of each point shows an upward trend (straight line).