Mathematical straight line and circle of students in secondary vocational schools

Go back to point O and make OE perpendicular to BC. Because OC score is ∠ACB, OE=OA, so BC is tangent.

AC=AD= 1/2BC, and the vertical diameter theorem shows that CE = BC and AC = ad, so this conclusion is drawn.

Pythagorean theorem shows that AC=6, so CD= 12, and the area of the ring is the area of the big circle MINUS the area of the small circle, which is extremely &; (oc^2-0a^2)=ac^2&； = 36 & Answer will get 2 points, and if the answer is accepted, you will get bonus points and 20 points.

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