1. Comprehensive formula problem of mathematics in the third grade of primary school
63÷7= 86-39= 400×8= 93-25=
34+28= 67+33= 500×4= 84÷9=
92- 16= 52- 18= 1200-700= 40÷8=
72÷9= 80-26= 9000-500= 53+69=
50÷7= 43+36= 25×4= 46+27=
1×325= 27+54= 45÷6= 750+250=
2500-2000= 80×7= 300×5= 4×40=
85+25= 96+25= 56÷8= 34÷4=
87-38= 650-320= 1400-500= 73-29=
300×5= 9000-500= 64-26= 87-53=
500×2= 84+50= 62+48= 72+ 19=
700×4= 660-90= 25+55= 34+56=
40×7= 4300-700= 86-24= 45+37=
60×5= 120+300= 100-55= 94- 19=
600×6= 700+900= 74+28= 72-48=
2. The comprehensive formula of mathematics in the third grade of primary school
Calculation problem:
27÷3×7 ? 3×6÷9 ? 25÷5×8
45+8-23 ? 63÷7×8 ? 24-8+ 10 ?
28÷4×7 ? 35+24- 12 48÷8×9 ?
40÷8×2 1 84÷4÷7 690+47×5?
205-35÷7 28+ 120×8 97- 12×6
26+25÷5 ? 148+28÷7 24÷3+730 ?
2 100-48×5 5 1+(304-204) 42 15+ 16÷8
(247+ 18)×7 ? 720-(360+ 18) 1080-5×80
(528+9 12)×5 ? 85×(38-34) ? 264+30÷6?
( 174+209)×2 ? 8 14-(278+322) ? 35×9+45 ?
769- (63÷7) 285+(300+372) ? 146×(2 1÷3)?
3. The third grade mathematics comprehensive formula problem
1 and Xiaohong average 95, Chinese 96, English 92, what's the math score? _____________________________________
2. Teacher Wu bought two footballs, teacher Zhang bought four basketballs, and teacher Wang bought 1 football, 1 basketball and three balls. Each of them spent the same amount of money. 1 How many balls is the price of football?
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Huanhuan and Lele bought stationery. Huanhuan bought three pencils and five erasers for 6.5 yuan, and Lele bought the same three pencils and seven erasers for 8.5 yuan. Xiaoxiao also wants to buy the same five pencils and four erasers. He brought 10 yuan. Is that enough?
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4. A football match, 45 minutes in the first half, half time 15 minutes. When Xiao Qiang entered the stadium at 9: 30, the first half had just ended. What time does the game start? When will it end?
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5. a square fountain with railings around it, with a total length of 48 meters. If a lawn with a width of 1 m is laid on the periphery of the fountain, how many square meters of turf is needed?
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4. The comprehensive formula of mathematics in the third grade of primary school
I. Calculation
998+7×8= 84÷(47-26)=
785+392-392= 5670÷7=
100-60÷6 = 18×3+55=
24-24÷6= 630÷70 = 63÷( )
300-9×20= 90+8 10÷9=
150+( )=900 ( )-780=780
680÷20=70-( ) 56-0÷7=
450÷5-5= ( )÷4=32……3
5+6+7=9+( )×3 678-479=
90×6-28= 14×6-6×8=
270÷9=5×( ) 350-99×2=
Second, use split method to calculate.
623÷5 449÷6
847÷4 258×3
5. The comprehensive formula of mathematics in the third grade of primary school.
1, a number written directly.
82-27= 62+25= 37+23= 180+20= 87-26=
56-46= 600-30= 130-50= 540+90= 80+640=
390-300= 46+64= 36÷9= 7×8= 63÷9=
3×6+5= 6+27+9= 24÷6-3= 64÷( 16-8)=
9600-600= 8080-80= 8000-3000= 35÷5=
2000×5= 44+8= 37- 18= 1300-500=
4800÷4= 1 1×9= 32÷8= 100-43=
5600+400= 800+200= 240×4= 15×6=
2. Calculate the following questions vertically.
635-478= 800-37= 504+297= 489+378=
Check calculation: Check calculation:
5 1÷8= 54÷7= 54÷6= 50÷9=
407×5= 739×6= 604×5= 3 12×6=