Mathematical problems (important processes)

Then let's say x kilometers.

The first meeting is x kilometers, the second meeting is 3x kilometers, and the third meeting is 5x kilometers.

The first meeting time: x/(45+36)=x/8 1 hour, Party A: 45 * x/8 1 = 5x/9km, and the distance to Party A: 5x/9km.

The second meeting time: 3x/8 1=x/27 hours, the route A: 45 * x/27 = 5x/3km, and the distance A: 2x-5x/3 = x/3km.

The third encounter time: 5x/8 1 hour, route A: 45 * 5x/8 1 = 25x/9km, distance A: 25x/9-2x = 7x/9km.

7x/9 x/3 = 40

4x/9=40

X = 90km km

Let x require the original quantity l and the increased quantity v, then

Lx/(L+v)=3%, which means 100Lx=3L+3v.

Lx/(L+2v)=2%, that is, 100Lx=2L+4v.

Then 3L+3v=2L+4v, which means l = v.

So x/2=3% or x/3=2%.

x=6%

Fill in 6% of the answers!