Current location - Training Enrollment Network - Mathematics courses - Urgent math problem! ! ! !
Urgent math problem! ! ! !
Standard answer:

Solution: 1 According to the meaning of the question, let the coordinate of a be (a, a/3), where A >;; 0, if B is to the left of C, and the coordinate is (b, 0), then the coordinate is (b+2, 0), then there are:

(a-b)^2+(3/a-0)^2= 1;

(a-b-2) 2+(3/a-0) 2 = 3/4 (hint: the square of AB| is equal to1; The square of |AC| is equal to 3/4)

Solve the equation: b= 1.5

So the coordinate of c is (3.5,0)

If b is to the right of c, let the coordinate of a be (a, a/3), where a >;; 0, the coordinate of B is (b, 0), then the coordinate of B is (b-2, 0), which is the same as understanding that the coordinate of C is (0.5, 0).

2. Let the coordinate of A be (a, a/3), where A

(a-b)^2+(3/a-0)^2= 1;

(a-b+2)^2+(3/a-0)^2=3/4

Solution: b=- 1.5

So the coordinate of c is (-3.5,0).

If B is to the left of C, let A's coordinate be (a, a/3), where a < 0 and B's coordinate be (b, 0), then B's coordinate be (b+2, 0), which is the same as understanding C's coordinate be (-0.5, 0).

To sum up, the coordinates of c are (3.5,0) or (0.5,0) or (-3.5,0) or (-0.5,0).