The second problem of sixth grade mathematics
First, the wafer is divided into two halves, then cut into the same number of small sectors, keeping the edge of the circle unchanged, and then two semi-circular pieces are inserted to get an approximate rectangle. The width of the rectangle is the radius of the wafer, and the length is the half circumference of the wafer, which is 3π cm, while the area of the original circle is 9π cm.