f(x)=[2 sin(x+π/3)+sinx]cosx-√3 sin？ x=[sinx+√3cosx+sinx]cosx-√3sin？ x

=2sinxcosx+√3cos？ x-√3sin？ x=sin2x+√3cos2x=2sin(2x+π/3)

1.f(x) =2π/2=π minimum positive period;

2. If x0 belongs to [0,5 π/12], let the inequality f (x0).

When x ∈ [0,5 π/12], 2x+π/3 ∈ [π/3,7 π/6], sin (2x+π/3) ∈ [-1/2,65438.

So f(x)min=- 1, so:-1

Range of real number m: m>- 1