=2sinxcosx+√3cos? x-√3sin? x=sin2x+√3cos2x=2sin(2x+π/3)
1.f(x) =2π/2=π minimum positive period;
2. If x0 belongs to [0,5 π/12], let the inequality f (x0).
When x ∈ [0,5 π/12], 2x+π/3 ∈ [π/3,7 π/6], sin (2x+π/3) ∈ [-1/2,65438.
So f(x)min=- 1, so:-1
Range of real number m: m>- 1