Solution: After passing through point B, BE⊥AD is at point E and BF⊥CD is at point F.

∵BE⊥AD,BF⊥CD,AD⊥CD

Rectangular bed

∴ED=BF,FD=BE

∠∠A = 30

∴BE=AB/2=5，AE=AB×√3/2= 10×√3/2=5√3

∠∠C = 30

∴bf=bc/2= 10,cf=bc×√3/2=20×√3/2= 10√3

∴ED= 10,FD=5

∴ad=ae+ed=5√3+ 10,cd=cf+fd= 10√3+5

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