It is sunny today. I was reading Mathematical Olympiad in Primary School at home, and suddenly I found such a problem: compare11111,1 165538. Suddenly, I became interested and took a pen and "brushed" it on the toilet paper. Soon, I found a solution Is to turn these two false fractions into fractions, and then use the law of fractions to make the same molecule.

The smaller the fraction and denominator, the greater the fraction. Solve111111

This question is very difficult. "Say that finish, I sarcastically said to my mother:" How tall you are, this topic is not a piece of cake for you! "Mom smiled:" OK, OK, I won't argue with you, but if you can solve this problem from two aspects, it will be a high level. " I listened to my mother's words and looked at the problem again. I couldn't help wondering, "There are other solutions." I was surprised and said, "Of course," and my mother said I wouldn't do it anyway. It seems that your level is still low. "I buckled my mother's words, and I was so angry that I did it again, proving that I am a high-level person. Finally, through my efforts, the second method came out, which is to compare their sizes by division. You see, if one number is less than another number, then the quotient of this number divided by another number must be a true fraction. Similarly, if one number is greater than another, the quotient of this number divided by another number must be greater than 1. Using this rule, I use1111÷11. Needless to say, it must be the closest two, so1111111//. 1 1 1× 1 1 1/ 1 1 1 1 1、 1 1 1 1 1 / Kloc-0/11111×11,so it is. 1 1 1 1 1/ 1 1 1 1。